symmetry within this molecule making it chiral.
Okay to make sure you fully understand everything we just covered try these two
questions and we'll go over the answers in just a little bit. For question one
identify the chiral centers. To find the answer to question one let's check each
carbon and see if there are four different groups. Hmm nope not enough
groups not enough groups for the next carbon this carbon has one two three
four different groups so yes this is a chiral center. Next remember double or
triple bond will never be a chiral center so this one is not a chiral
center. This next carbon doesn't have enough groups the next carbon has one
two three and four different groups so yes this is another chiral center and
this end carbon is a common mistake it has enough groups but there are two of the
same groups our methyl groups but we need all four groups to be different so
this is not a chiral center. There are only two chiral centers in this molecule.
For question two label each molecule as chiral or achiral
To find the answer to question two remember we are looking for lines of
symmetry, if there is a line of symmetry within the molecule then it's achiral
like this first one is. Here is another hidden line of symmetry we can count the
number of carbons on either side and see that we can cut this molecule in half
and it would be the same since there are 1, 2, 3 carbons on the left and 1, 2, 3
carbons on the right making this molecule achiral. Now for the remaining
molecules there is no line of symmetry no matter how we try to cut them down
the middle they are never the same so these both are chiral.You can find other
helpful videos right here and if you would like additional homework help
tutoring or other resources you can find that all in the description box and
remember stay determined you can do this