I've been doing a ton of videos on the mechanics of
taking the Laplace Transform, but you've been sitting
through them always wondering, what am I learning this for?
And now I'll show you, at least in the context of
differential equations.
And I've gotten a bunch of letters
on the Laplace Transform.
What does it really mean?
And and all that.
And those are excellent questions and you should
strive for that.
It's hard to really have an intuition of the Laplace
Transform in the differential equations context, other than
it being a very useful tool that converts differential or
integral problems into algebra problems. But I'll give you a
hint, and if you want a path to learn it in, you should
learn about Fourier series and Fourier Transforms, which are
very similar to Laplace Transforms. And that'll
actually build up the intuition on what the
frequency domain is all about.
Well anyway, let's actually use the Laplace Transform to
solve a differential equation.
And this is one we've seen before.
So let me see.
So let's say the differential equation is y prime prime,
plus 5, times the first derivative, plus
6y, is equal to 0.
And you know how to solve this one, but I just want to show
you, with a fairly straightforward differential
equation, that you could solve it with the Laplace Transform.
And actually, you end up having a
characteristic equation.
And the initial conditions are y of 0 is equal to 2, and y
prime of 0 is equal to 3.
Now, to use the Laplace Transform here, we essentially
just take the Laplace Transform of both sides of
this equation.
Let me use a more vibrant color.
So we get the Laplace Transform of y the second
derivative, plus-- well we could say the Laplace
Transform of 5 times y prime, but that's the same thing as 5
times the Laplace Transform-- y prime.
y prime plus 6 times the Laplace Transform of y.
And let me ask you a question.
What's the Laplace Transform of 0?
Let me do that.
So the Laplace Transform of 0 would be be the integral from
0 to infinity, of 0 times e to the minus stdt.
So this is a 0 in here.
So this is equal to 0.
So the Laplace Transform of 0 is 0.
And that's good, because I didn't have space to do
another curly L.
So what are the Laplace Transforms of these things?
Well this is where we break out one of the useful
properties that we learned.
Let me write it over here.
I think that's going to need as much
real estate as possible.
Let me erase this.
So we learned that the Laplace Transform-- I'll do it here.
Actually, I'll do it down here.
The Laplace Transform of f prime, or we could even say y
prime, is equal to s times the Laplace Transform of
y, minus y of 0.
We proved that to you.
And this is extremely important to know.
So let's see if we can apply that.
So the Laplace Transform of y prime prime, if we apply that,
that's equal to s times the Laplace Transform of-- well if
we go from y prime to y, you're just taking the
anti-derivative, so if you're taking the anti-derivative of
y, of the second derivative, we just end up with the first
derivative-- minus the first derivative at 0.
Notice, we're already using our initial conditions.
I won't substitute it just yet.
And then we end up with plus 5, times-- I'll write it every
time-- so plus 5 times the Laplace Transform of y prime,
plus 6 times the Laplace Transform of y.
All of that is equal to 0.
So just to be clear, all I did is I expanded this into this
using this.
So how can we rewrite the Laplace Transform of y prime?
Well, we could use this once again, so let's do that.
So this over here-- I'll do it in magenta-- this is equal to
s times what?
s times the Laplace Transform of y prime.
Well that's s times the Laplace Transform of y, minus
y of 0, right?
I took this part and replaced it with what I have in
parentheses.
So minus y prime of 0-- and now I'll switch colors-- plus
5 times-- once again the Laplace Transform of y prime.
Well we can use this again.
So 5 times s times Laplace Transform of y, minus y of 0,
plus 6 times the Laplace Transform-- oh I ran out of
space, I'll do it in another line-- plus 6 times the
Laplace Transform of y.
All of that is equal to 0.
I know this looks really confusing but we'll
simplify right now.
And we could get rid of this right here, because we've used
it as much as we need to.
So now we just simplify.
And notice, using the Laplace Transform, we didn't have to
guess at a general solution or anything like that.
Even when we did a characteristic equation, we
guessed what the original general solution was.
Now we're just taking Laplace Transforms, and let's see
where this gets us.
And actually I just want to make clear, because I know
it's very confusing, so I rewrote this part as this.
And I rewrote this thing as this.
And everything else is the same.
But now let's simplify the math.
So we get s squared, times the Laplace Transform of y-- I'm
going to write smaller, I've learned my lesson-- minus s
times y of 0.
Let's substitute y of 0 here. y of 0 is 2, so s times y of 0
is 2 times s, so 2s, distribute that s, minus y
prime of 0.
Y prime of 0 is 3.
So minus 3, plus-- so we have 5 times s times the Laplace
Transform of y, so plus 5s times the Laplace Transform of
y, minus 5 times y of 0. y of 0 is 2, so minus 10.
Minus 10, right?
5 times-- this is 2 right here-- so 5 times 2, plus 6
times the Laplace Transform of y.
All of that is equal to 0.
Now, let's group our Laplace Transform of y terms and our
constant terms, and we should be hopefully
getting some place.
So let's see, my Laplace Transform of y terms, I have
this one, I have this one, and I have that one.
So what am I left with?
Well let me factor out the Laplace Transform of y part.
So I get the Laplace Transform of y-- and that's good because
it's a pain to keep writing it over and over-- times s
squared plus 5s plus 6.
So those are all my Laplace Transform terms. And then I
have my constant terms. So let's see, I have 1s, so minus
2s, minus 3, minus 10, is equal to 0.
And what can we do here?
Well, this is interesting, first of all.
Notice that the coefficients on the Laplace Transform of y
terms, that those are that characteristic equation that
we dealt with so much, and that is hopefully, to some
degree, second nature to you.
So that's a little bit of a clue, and if you want some
very tenuous connections, well that makes a lot of sense.
Because the characteristic equation to get that, we
substituted e to the rt, and the Laplace Transform involves
very similar function.
But anyway, let's go back to the problem.
So how do we solve this?
And actually, let me just give you the big picture here,
because this is a good point.
What I'm going to do is I'm going to solve this.
I'm going to say the Laplace Transform of
y is equal to something.
And then I'm going to say, boy, what functions the
Laplace Transform is at something?
And then I'll have the solution.
If that confuses you, just wait and hopefully it'll make
some sense.
From here until that point it's just some
fairly hairy algebra.
So let's scroll down a little bit, just so we have some
breathing room.
And so I get the Laplace Transform of y, times s
squared, plus 5s, plus 6, is equal to-- let's add these
terms to both sides of this equation-- is equal to 2s plus
3 plus 10-- oh, that's silly-- plus 13.
This is minus 13 here.
A phone call.
Who's calling?
I think it's some kind of marketing phone call.
Anyway, 2s plus 13, and now what can I do?
Well.
Let's divide both sides by this s squared plus 5s plus 6.
So I get the Laplace Transform of y is equal to 2s plus 13,
over s squared plus 5s plus 6.
Now we're almost done.
Everything here is just a little bit of algebra.
So now we're almost done.
We haven't solved for y yet, but we know that the Laplace
Transform of y is equal to this.
Now, if we just had this in our table of our Laplace
Transforms, we would immediately know what y was,
but I don't see something, or I don't remember anything we
did in our table that looks like this expression of s.
I'm essentially out of time, so the next video we're going
to figure out what functions Laplace Transform is this.
And it actually turns out it's a sum of things we already
know, and we just have to manipulate this a little bit
algebraically.
See you in the next video.