(mystical music)
(upbeat music)
- Hello, and welcome to the Laramy-K Optician Works
Training Center, where today we're going to cover
single vision finishing layout work
for a job that has an OC height requested.
That means that we're not only going to decenter
the lens horizontally for PD,
we're also going to move it vertically
to match the OC height requested.
We'll do three examples,
and I'll show you what that looks like in the blocker.
First things first, don't panic.
(rumbling)
This looks like a whole lot more than
what we've been doing.
But it's actually just two little tiny additions.
And one of them you are already familiar with.
Probably both of them you're familiar with.
We just added the cylinder in an axis
to the prescription, I'll explain why that's
a little bit more important
when we get to superlens in a minute.
And we added in OC height, that's it.
Other than that, it's the exact same thing
that we've been doing in the last three videos,
which you should have watched.
I have superframe, superframe has a boxing
system measurement of 53-19.
I've got enough power here, I'm gonna double check that
just to make sure that frame is correct.
53.
19, we're good.
So we have a framed PD geometric-centered center of 72.
We have a monocular PD of 31/33,
so I'm gonna need two numbers from my frame.
So I'm gonna take my 72 divided by two and have 36.
36 minus 31
gives me five millimeters in decentration in my right.
36 minus 33 gives me three millimeters in my left.
Same thing that we've been doing.
If I took superlens, (epic music)
and I was in the blocker just the way we've been doing it,
that would be on center, I would move this
over five millimeters.
Now here's where things change out just a little bit.
I've mentioned a couple of times that
when I have a sphere,
I can put this dot in the center and I can
rotate this lens anywhere I want around that.
Now that I've added the cylinder in the axis,
these two outer dots become critical.
They must remain in the horizontal position.
I can't rotate this around anymore.
So I would have to be extremely careful,
keeping that straight.
Moving it over in the blocker, and I'll show you there,
and attaching my block.
Same here, I can't do this,
can't do that; it must remain perfectly horizontal
so that my lens stays in axis.
The other thing that's changing on this one
is that the person who's put the job in
has requested an OC height.
That means that this person,
their eye is not here,
it's not here.
Their eye is here in this frame.
So I'm gonna be moving my OC over and up.
They're not here, they're not here,
they're here, in and up.
How do I determine how far I'm going to move that up?
Much in the same we do as a monocular PD.
I take my B, which is 28,
I split it in half, 14-14,
and I take my OC height of 16.
16 minus 14 says that I'm gonna be
moving this lens two up.
16 minus 14, two up.
For this in the blocker, and we'll look at that
in just a second, I will be going five over
and two up.
For this, I will be going three over
and two up.
Let's see what that would look like in the blocker.
For example number one, we ended up with,
say, that we needed five in and two up,
and this exactly how you're going to want
to think about this.
We go to a blocker, and you're ready to do some work,
it's five in and five up.
Two in, two down, three in, whatever it might be,
you want those two in your head.
Since this manual blocker doesn't adjust
for vertical movement, take a quick look
at the reference points.
Your darker or bold horizontal lines
are in five-millimeter increments.
The thinner ones are in one-millimeter steps.
Let's go ahead and load up a block.
That's five over.
Now for vertical decentration, up or down,
the grid doesn't move.
So we have to count.
That would be zero, that's five over
in the right.
We have a lens with the cylinder and the axis,
so I'm keeping those three.
X is perfectly horizontal right where they are.
And now I need to count.
One.
Two.
Oh.
Now I'm at a little bit of a disadvantage here
because I have a camera obviously over this
so I can't put my head over and look straight down.
Camera's in the way, otherwise my head would be
in the way as well.
So if I'm half a millimeter off or something,
please don't send me any hate mail.
So five over, two up.
In right.
Turn that over, in and up.
That's good.
My left set, I have three over
and two up.
Three over...
X is horizontal like that,
and one...
two up.
Looks good.
Flip that over.
(mumbles)
In, in and up.
I just shot example one, went into the office,
I did some editing, and I realized
I need to slow down a little bit.
For some reason (mumbles),
too much coffee in the morning or something,
I seem to be rushing through.
I'm gonna do this one in a little bit different way,
and unfortunately you are just gonna be
kind of staring at my back and listening
to my mind work.
But just kind of bear with me
and see how I work through this and think about it.
We'll go back to the other way after this example.
Nothing new, nothing special there.
We do have a cylinder in an axis,
so obviously I'm gonna have to keep my lens
from rotating around.
I've go a monocular PD, I do have an OC height,
I do have a B, so I'm gonna need to
figure some stuff out here.
I have a frame with a boxing system of 54-17.
That's 71.
71 divided by two
gives me 35.5.
That means I can fill this in.
Alright.
Because I have an OC height, I'm gonna need to
do basically the same thing with my B
as I do with my As.
31 divided by two is 15.5.
And for my decentration for horizontal
for my PD, got 35.5...
minus 32,
minus 33.
35.5 minus 32 is
3.5 in.
35.5 minus 33,
2.5 in.
So far, so good.
Got an OC height of 18
minus 15.5, where is that?
That's this, half my B,
I'm moving up from the center of my eye wire opening;
just as I do horizontally, I do the same thing vertically.
I need to move this up 18
minus 15.5.
Need to move this up 2 1/2.
Alrighty, I think we're in a good place.
Obviously, if you were taking a practical exam
of some kind and they said do the layout calculations
for single-vision job just like this,
this is exactly what you would want to do.
I mean, exactly.
Again, why do I use a calculator?
Because I don't wanna make a mistake.
I don't wanna make an error and ruin a lens,
or fail a test, for that matter.
And what is this all tell us?
It tells us that our human,
the person wearing this pair of glasses,
their eye, as it sits within this frame,
is not here.
It is not here, as we've been doing.
It's up here, not rare.
We have enough power that we'd want to do
an OC height, bring that lens up just a tiny little bit,
bring that OC up here.
Eye is not here, eye is not here,
eye is up here.
If I take superlens, (epic music)
and I put it into the blocker, which we'll do in a minute,
that OC is not there.
It is not there.
I want it up here.
It is not here, it is not here.
But I need to move it up here.
And I need to keep these horizontal
because I have a cylinder
and I have an axis.
Quick review, where did numbers come from.
Boxing system for a frame is 71.
71 divided by two gives me 35.5,
distance split down the middle center to center.
My human, my PD, 32 and 33.
18 is my OC height, that's how far I wanted this
lens OC moved up from the bottom of the eye wire
to where the pupil is.
How do I calculate that?
I split my B, and I move it up
2 1/2 millimeters.
This is what it would look like in the blocker.
For example number two, I have got 3 1/2 and 2 1/2.
Got 3 1/2.
And 2 1/2.
Over one, 2 1/2.
(mumbles)
Double check what I got there,
over and up, good.
For my left, it's 2 1/2 and 2 1/2.
2 1/2, keep those Xs horizontal on one,
2 1/2.
Double check quick.
In and up.
Good to go.
Example number three.
You know I can't help but notice nobody
ever asked me to sing and nobody ever actually
asked me to read more poetry.
(tsking)
We have superframe.
Superframe has a boxing system measurement
of 48-21.
If I add 48 and 21, I get 69.
I have a monocular PD, so I need to split that
34 1/2-34 1/2.
My A, I would double check I've got enough power,
make sure that I've got 48 there.
I do.
Big wide bridge of 21, let's make sure that's correct.
21, we're good.
And we have a B this time.
We've got enough power, we're doing OC height,
let's make sure that B is correct at 29.
Beautiful.
If I take my monocular PDs
and I subtract them from my
geometric center of my eye wire openings,
I need 6 1/2 in in my right,
7 1/2 in in my left.
This job calls for an OC height of 18,
meaning from the bottom of my eye wire,
or where the lens would sit within the eye wire,
according to the boxing system,
I want the OC placed 18 millimeters above that point.
How do I know how to move that in the blocker?
The blocker works the same way horizontally
as it does vertically.
If I take half of my B of 29
divided by two, I have 14 1/2.
If I take my 18 OC height and I subtract my 14 1/2,
I'll need to move my OC up 3 1/2
millimeters from that center line or center point.
(epic music muffles speaker) superlens,
and I head over to the blocker,
because I have a cylinder in an axis.
I'm gonna keep my three dots perfectly centered,
OC orientation marks.
And I'm gonna need to put that
OC right there.
And I'm gonna need to put the OC
right there.
Let me show you what that'll look like in the blocker.
Example number three says that I have got 6 1/2,
(mumbles) quite a bit, 6 1/2 over
and 3 1/2 up.
6 1/2 over
and 3 1/2 up.
One, two, 3 1/2.
(mumbles)
Six over and up, looks good.
♪ One to go, one to go ♪
This one is 7 1/2.
And 3 1/2 up.
At B zero.
Over 7 1/2.
One, two, 3 1/2 up.
And again, I might be a little off,
it's really hard for me to see this
at the angle I am, but that should be really close.
And looking at my left, the in and up.
It's good.
Alright.
Thank you so much for watching,
I will see you again next week.
If you are, in fact, ready to start to finish,
please give us a call at Laramy-K
for all your uncut lens needs.
They're up here, they're up in--
(dog barking)
(bleeping)