Leah here from Leah4sci.com/MCAT and in this video, I'll show you how to work through Trigonometry
related problems on your MCAT without a calculator. When you think of Trigonometry you'll probably
thinking SOHCAHTOA, so let's see how that applies to the MCAT. SOHCAHTOA breaks down
as follows: We have Sin, Cos and Tan. Without going into too much boring Trigonometry, let's
see how to look at this Triangle. When given some angle theta, you put this
line to represent the angle in question, the two sides of the triangle that form the right
angle, the adjacent is the side of the triangle that is near your angle, the opposite is the
side of that triangle that doesn't touch your theta value but is still part of that ninety
degree or right angle, and finally the line the connects the adjacent and the opposite
but is not part of that ninety degree that is called your Hypotenuse. We'll use SOHCAHTOA
to find Sin, Cosin and Tangent. Sin is Opposite over Hypotenuse or typically this line over
here. Cosine is Adjcent over Hypotenuse and is referring to this line over here and Tangent
is simply the Opposite over the Adjacent. If you learn Trigonometry you worked on many
different angles and set them up in many different ways.
But on the MCAT, the majority of triangles that show up will be set up like you see this
one where the Sin refers to your Y value and so we'll write it as SYN to remind you that
Sin is Y. Your Cosin typically refers to your X value and so we'll add the x at the end
to remind you that Cos refers to X. And since Tangent is Opposite over Adjacent, Tangent
is simply going to be Y/X. Now I see majority of the time if you're dealing
with an inclined plane, you'll find that your coordinates change but if you're dealing with
any Physics Kinematic type of problems you're okay to use Sin Y and Cos x.
Before we can go into a Math problem, we have to know how to calculate the Sin, Cos, Tan
values without using a calculator. Since Tan is Y/X that's simple division and we won't
look at that. Instead I want to focus on the values for Sin and Cos as we want to think
about them on the MCAT. For example, you may get a question that asks you to calculate
the Sin value or Cos value of 45 degrees. But if you think the Cos of 45 is radical
two over two, that may be correct in a Trigonometry class but how are we going to do that in the
MCAT? Now, what you need to know is a simple rounded
number that you can easily use in calculations to help you quickly work through the Math
and come up with the correct answer. I'm going to show you the proper values for
Sin and Cos but I also want to show you a trick and a shortcut to help you quickly come
up with the numbers even if you get stuck or even if you panic. We'll look at this simple
coordinate system where you have zero degrees to the right, ninety degrees above and simply
work our way around, a hundred eighty degrees left and two hundred seventy at the bottom.
I want you to imagine that starting from the origin, I draw a line that has a unit length
of one. Remember the trick, we spelled "Syn" with a Y and "Cosx" with an x. This is to
help you quickly identify your Sin and Cos values. In fact let's create a table and match
the trick to the values on the table. We have the table, now let's see how this diagram
will help us come up with the values. If this line with the unit length of 1 is
sitting parallel to the X-axis at zero degrees, the Cos or the X-value is one because the
line has a length of one a height of zero so the x-value or the length of one gives
us a Cosx of one for zero degrees and Syn of zero for zero degrees because we haven't
raised it anywhere in the Y direction. Keep in mind this is not drawn to scale but imagined
that I now raised this line to Thirty degrees. If draw it to scale the tip of that ray will
be halfway up between x and y and that means the Syn value of Thirty degrees is half or
point five, the Cosx value on the calculator comes to .866 but on the MCAT you can get
away with using point Nine. Now you can memorize point .866 but this trick will be easier if
you'll recognize that point eight six six is very close to point nine and that on the
MCAT, when you round, your answer will typically be close enough.
If we raise that line to Forty five degrees, notice that our Cosx value keeps getting smaller
and smaller. Here we're at one, here we're at point nine, here we get to something that
the calculator will call point seven o'seven, for the sake of memorization, we'll just keep
it at point seven. The Syn value or the Y value has gone from
zero to point five and now we're slightly higher at point seven o'seven which ones again
is rounded to zero point seven. Let's take this ray and raise it up even more moving
up to Sixty degrees. Notice that the x-value is halfway between the origin at a length
of one giving me a Cosx value of point five. The Syn value on the other hand is getting
higher and higher and is nearly at the top for a calculated value of point Eight Six
Six and a rounded value of zero point nine. If we turn our ray even more and make it parallel
to the Y-axis pointing directly at Ninety degrees, notice that we have nothing in the
X direction because the ray is sitting on that Y-axis giving me a Cosx value of Zero
but because the ray is a length of one pointing straight up at Ninety degrees, we get a Syn
value of one. Now that we have our numbers I want you to
notice this pattern. Starting from Cosx zero degrees we have 1 and then we drop by point
two, point nine, point seven, point five. Ones we're at point five, we drop to zero.
For Syn, we have the exact opposite pattern because we're starting with zero, we jumped
to point five and then increase point seven, point nine, one.
So on your MCAT, yes you can use point seven, point eight six six if you have to but if
you want to have that ballpark first to figure out where to start with your angles. Draw
that quick sketch with the zero for Cosx and then just write one, point nine, point seven,
point five and figure out where you stand based on the angle you were given. These are
the main angles that I want you to memorize but you can always infer in-between angles
based on what we have here. So for example if your MCAT question asks
you to calculate something related to Thirty Seven degrees. Thirty seven is parkway between
Thirty and Forty five so the sign value will be something near point six, Cosx value will
be something near point eight and you can apply this everywhere.
I'm also including a hundred and eighty degrees in this trick to remind you that if you pass
the ninety degree mark, you're going to the negative x territory which means all the values
will be the same except that a Cosx of a hundred and eighty will be on in the opposite direction
or negative one and Syn of course will still be zero. Let's apply this to a problem that
may show up on your MCAT. A child pulls on a 4kg wgon with a gorce of
9N. Find the initial acceleration of the wagon if the force is applied at 30˚ to the ground.
The physics portion to this question will be tackled in the Physics videos found at
leah4sci.com/MCATPhysics. But because I wan to focus on Math, I'll jump straight into
the equation. If we have Force equals to Mass times Acceleration (F=ma) and we wanna solve
for acceleration, we divide by mass, divide by mass giving me the Formula Acceleration
is equal to Force over Mass (a=F/m). But we can't use the total force we can only
use the force apply to the direction of motion. I'll simplify the wagon as rectangle, here
we have the child pulling on the wagon with an angle of thirty degrees to the ground.
If the force of Nine Newton is applied thirty degrees, we only want the component in the
x-direction since the acceleration will be in the X-direction. That means we have to
take the initial force and break it into its X and Y components to know what to use in
the situation. Force in the x direction equals force times
the Cos of thirty degrees. How did I know to use Cos, remember the trick we're spelling
Cos with an x reminding us that the standard triangle uses Cos for the X-value. Cosx of
thirty according to our shortcut is point nine, we're not gonna use point eight six
six because in Math will take too long. So we have nine newtons times Cosx of thirty
which is zero point nine. Nine times nine is Eighty one but because
the decimal is one space to the left we move the decimal back one space to the left and
our answer to giving us Eight point one. To solve for acceleration we plug in the value
for force, eight point one newtons, the value for mass, four kilograms, we round eight point
one to eight and so eight divided by four equals two and the units for acceleration
are meters per second squared. Be sure to join me in the next video where
I show you how to solve logs without a calculator as it'll show up in pH, pKa and similar type
questions. Are you stuck on a specific MCAT topic? I
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