- [Instructor] So, a simple pendulum
is just a mass hanging from a string.
And if you are to pull this mass,
sometimes it's called a pendulum bob,
if you are to pull it back and then let go,
gravity would act as a restoring force
and this mass would swing back and forth over and over.
And because this simple pendulum
is a simple harmonic oscillator, it's motion.
Its angle as a function of time
would be accurately described by a sine or a cosine graph.
So, in other words,
if you are to pull this back initially by 15 degrees,
you might get a graph that looks something like this.
Now, every simple harmonic oscillator
has a characteristic period of motion.
Now, the period of motion is the time it takes
to complete one full cycle.
So, the time it takes to swing from here
all the way to there,
all the way back to here,
would be one full period.
And in this graph, I've written it as .5 seconds,
but the period of every simple pendulum
is not gonna be .5 seconds.
The period of a simple pendulum
depends on the characteristics of that pendulum
and the environment that it's in.
So, to derive this formula for the period of a pendulum,
you would need calculus.
So, I'm just gonna write it down
and give you a quick tour and compare it
with the period formula for a mass on a spring,
to the period of a pendulum
is gonna be equal to two pi times the square root
of the ratio of the length of the pendulum, L,
so the length of that string here, the length L,
divided by g, the gravitational acceleration
of the planet that the pendulum is being used on.
Now, if you look at this
and you've been paying attention in physics,
you might be like, "Wait, that looks really similar
to the formula for the period of a mass on a spring."
So, if you are to take a mass on a spring,
displace it 15 centimeters,
you'd get a similar graph
and this would also have a characteristic period of motion.
And if you wrote down the period for a mass on a spring,
it looks like this, its period for a mass on a spring
is also two pi, so that's identical.
And then, it's also the square root of a ratio,
but instead of L over g for the mass on a spring,
it's m, the mass of the block connected to the spring,
divided by k, the spring constant of the spring.
So, one obvious similarity between these two formulas
is just their format.
They're both a two pi times a square root of a ratio,
but another important similarity between these
that might not be evident
is that neither of these formulas
depend on the amplitude of the motion.
So, the period of a pendulum
does not depend on the amplitude of the motion
and the period of a mass on a spring
also does not depend on the amplitude of the motion.
What I mean by that
is if you are to pull this pendulum back,
instead of 15 degrees,
pull it back 20 degrees and let go,
it would have farther to swing.
So, its motion might look something like this,
and we get down farther and it would get back up,
but it would take the exact same amount of time.
The period would not change
if you pull this amplitude back farther.
Same goes with this mass on a spring.
Instead of pulling it 15 centimeters,
let's say you pulled it 20 centimeters, again,
this would start up higher.
It would get down lower.
But the time it takes to complete one full cycle
would not vary as you vary this amplitude.
And that might seem weird.
You're like, "Wait, don't these objects
have farther to go now
that you've pulled it back to a larger amplitude?"
That's true, they'll both have farther to travel,
but they'll be going faster now.
And faster motion over a bigger distance is gonna offset.
And the amplitude does not affect the period
of the motion of a pendulum or of a mass on a spring.
As for the differences, well,
the denominator here for the mass on a spring
depends on k, and that's the spring constant k,
and that should make sense.
More spring constant means you get more restoring force,
the spring force is the restoring force here.
More restoring force means this mass
is gonna be moving faster.
That means it's gonna take less time
to go through a full period.
So, dividing by a bigger number, bigger spring k,
gives you less period.
That's also true here but it's not k.
The force that's the restoring force for a pendulum
isn't a spring, it's the force of gravity.
So, mg depends on the g.
So, a bigger g would give you a bigger restoring force
over here for the pendulum.
That means the pendulum could be moving faster.
Moving faster means it's gonna take less time
to complete a full period.
So, dividing by a bigger g, if you took this pendulum
to the surface of Jupiter or something,
where the g is bigger,
it would swing back and forth faster.
It would take less time to complete it
because that restoring force is bigger.
So, even though these denominators are different letters,
they're arriving from the same source.
They're both arriving because the restoring force
is larger when you increase these denominators,
which increases the speed of the object.
Now, maybe the biggest difference here
is that the numerator here
for the mass on a spring depends on mass,
but nowhere is mass to be found
in this period of a pendulum.
The period of the pendulum does not depend on the mass.
Now, this is kind of interesting.
So, you know, really big, heavy person gets on a swing,
swings back and forth,
very light child gets on the same swing,
they will take the same amount of time
to complete a full cycle.
Their mass does not factor in here
to the period of pendulum,
but it does for the mass on a spring, why is that?
Well, bigger mass on a spring
gives you more inertia in the system.
If you have more inertia in the system,
it's more sluggish to movement.
It's gonna go slower.
That means it's gonna take more time
to complete a full cycle.
Now, you might think, "Wait a minute.
don't that hold true up here?
Look, if we have a bigger mass pendulum bob,
that should increase the rotational inertia.
And so, that should make this take longer.
It should be more sluggish to movement.
It should take longer to go through a full period."
But look at the restoring force is also, for a pendulum,
proportional to mass.
So, if you increase the mass of this pendulum,
you do get more inertia,
but you're getting more restoring force
because the restoring force is gravity.
Those completely offset
mass does not end up showing up into this pendulum formula,
even though it does down here.
So, the spring force is not proportional to mass.
Spring force is kx.
Increasing the mass of this block on the end
does not increase the spring restoring force.
So, this mass stays in the numerator here,
but it does not affect the period of a pendulum.
So, why does this L show up then?
Why is it length of the pendulum in the numerator?
Well, the rotational inertia does get increased
when you increase the length of the pendulum.
But increasing that length
that does not increase the force of gravity.
If you wanna get technical,
rotational inertia is proportional to length squared,
but the torque would only be proportional to length.
That's why only one L shows up here.
Long story short, if you increase the length of a pendulum,
you're gonna increase the inertia of that pendulum.
That's gonna make it take longer
to go through a full cycle.
This is while I go into the park
and finding the long swings.
The longer the swing, the longer it actually takes,
the more time it actually takes to swing back and forth.
I think that's more fun than the little short swings
that go back and forth really quick.
So, let's try a sample problem
to see how this period formula works.
Let's say you went to the park.
You're 60 kilograms.
You're swinging on a swing
and your friend pulls you back 20 degrees
on a swing that's one meter in length.
Let's find the period of the motion.
So, in other words, the time it takes
to go all the way to here
and then all the way back to there.
We use the period formula for a pendulum.
It's two pi, root L over g.
And so, we would do two pi times the square root,
the length here is the length of the string here.
So, one meter, technically,
it'd be to wherever your center of mass is,
but we're gonna assume our center mass
is right here at the end,
divided by g, well, we're on earth, I'm assuming,
so, 9.8 meters per second squared.
If you solve all of that,
you get a period of about two seconds exactly.
So, this swing would have a period of about two seconds.
Now, notice we did not use this 20 degrees.
That's the amplitude.
This period does not depend on the amplitude.
We also did not use the fact that I was 60 kilograms.
The period of a pendulum also does not depend
on the mass of the bob at the end of the pendulum.
We only use the length and if you're on earth,
the denominator here is always gonna be 9.8.
Now, one thing I should be clear about is that a pendulum
is technically not a perfect simple harmonic oscillator.
It's only approximately a simple harmonic oscillator.
So, this formula here is only approximately correct,
but for small angles, it's almost perfect.
So, at 20 degrees,
this formula is only gonna be off.
The error's only going to be about 1%,
which isn't bad.
If you get this back to like 70 degrees,
even then, the error's only around 10%.
So, this is a really, really good approximation
if you're in small angles, like around 20 to 30 degrees.
The bigger the angle gets though,
the worst the approximation gets.
For small angles, most physicists just treat a pendulum
as if it's a perfect simple harmonic oscillator.
As you get to those higher angles though,
you gotta be careful.
This can start deviating more significantly
from the actual value.
So, to recap, the period of a pendulum
depends on the length of the pendulum
and the surface gravity of the planet that you're on.
It does not depend on the amplitude
or the mass of the pendulum.
And the form it takes is very similar
to the period of a mass on a spring
where the numerator increases
due to increased inertia
and the denominator increases
due to increased restoring force.