In this video, I want to go ahead and talk
about thermodynamics and kinetics.
I remember that when I was first learning about these two things
in the context of chemical reactions,
I used to hear phrases like, oh, this chemical reaction--
let's say hypothetically A going to B--
is kinetically favorable, so it must proceed.
But then the next day when I go to class,
I'd hear another statement that said, oh, well this reaction
A going to B is thermodynamically favorable,
so it must proceed.
So in this video, I want to go ahead and clarify these two
statements for you and really understand
what it means to thermodynamically favored
and/or kinetically favored.
So to get it started, I've already drawn two plots so
that we can plot out the free energy change that
occurs for the forward reaction-- we'll do that
on the left side-- and the reverse reaction,
which we'll do on the right side.
So before we get into that, let's
go ahead and label our axes.
Our y-axis in both cases will be measuring
free energy, which is in units of joules.
Then our x-axis will be an abstract dimension
called the reaction coordinate, which essentially allows
us to monitor the progress of a reaction.
So now I'm going to go ahead and say
that the forward reaction we'll draw out in this teal color.
And the reverse reaction we'll go ahead and draw out
in this pink color.
So let's go ahead and start with the forward reaction.
So I'm just going to go ahead and say
that the forward reaction has a negative delta G value.
So remember that means it's spontaneous,
and visually that means that our reactants start off
at a higher free energy than our products.
Now, this of course means that the reverse reaction, which
will have the same magnitude of delta G, that
is the free energy change, will be at the same numerical value.
But of course, since the reaction
is going the opposite direction, the sign of delta G
will be now positive.
And visually, we're saying essentially
that our reactant, which in this case is B,
starts our at a lower free energy than our product,
which is A.
Now thus far in drawing this free energy diagram,
we've just been talking about thermodynamics.
But it turns out that there is also a kinetic energy
barrier for the conversion of reactants to products,
regardless of whether the reaction is
spontaneous or non-spontaneous.
This kinetic barrier of energy is
referred to as the free energy of activation,
or simply activation energy.
So I'm going to go ahead and put in parentheses E sub A, which
we'll say stands for activation energy.
And remember that delta G of course
is talking about thermodynamics.
With that said, let's go ahead and add this kinetic energy
barrier to our diagrams.
And we can do this by understanding
that the activation energy is defined as the amount of energy
that is required to form a high-energy intermediate
during the course of the reactions.
In other words, in our hypothetical reaction
of A going to B, it proceeds through an intermediate,
that is a high-energy chemical product that
won't last very long, but is important in the conversion
of A to B or vice versa.
So in our diagrams here, we can go ahead
and indicate that there is some intermediate, so
in between our reactants and our products, that
is at much higher energy than everything else.
And we can go ahead and then connect the dots.
So go ahead and essentially draw a line from reactants
to products that includes our high-energy intermediate.
And this ultimately allows us to see
the presence of the activation energy
as well as the change in free energy.
So let's go ahead and actually label these things.
So on the left side here, remember our change
in free energy, which is looking at our reactants
compared to our products-- we're ignoring this little bump.
The change in free energy, which I'm
going to indicate with the green line,
extends between these two points.
And the same on the right side, just again extending
between the start and endpoints of our reactions.
So I'll go ahead and indicate that this green line
in both cases refers to our delta G values.
And in a different color, let's say red,
I'm going to go ahead and indicate the activation
energy, which takes into account the change
in energy between the high-energy intermediate
and the reactants.
So in the case on the left, that change
is indicated here with red.
And on the right side, the change
between the intermediate and the reactant
is a bit longer, so we'll go ahead and indicate that here.
Now, activation energy is an important quantity
to take into account, because in order for molecules to react,
they must have enough energy to overcome this activation energy
barrier.
Essentially, in the case of a spontaneous reaction
for example, I think of it like the energy one
needs to get a ball to start rolling down a hill.
We all know that gravity will make a ball
roll down a hill, which is like a negative delta G value,
it's telling us that the reaction
is very thermodynamically favorable.
But we need to sometimes give the ball push in order
for the reaction to occur.
And so that's kind of this little help
that it needs to go over before it can actually proceed.
For a non-spontaneous reaction, the idea
is essentially the same.
We still need to have some activation energy.
But in addition, because it requires an input of energy,
we can think about it as rolling ball up a hill
instead of down a hill.
Now in general, the idea is that the lower this free energy
change, the faster a reaction will occur.
And remember I'm saying faster, so I'm talking about kinetics.
I'm talking about the rate of a reaction.
So just to write that out, the activation energy, the smaller
it is, the faster the reaction will proceed.
Now in biochemistry in particular,
it's really important to distinguish between these two
terms of thermodynamics and kinetics,
which we've drawn out in our diagrams
as the change in delta G over the change in activation
energy.
Because many biochemical reactions in our body
are kinetically unfavorable, that
is to say they have a very high energy of activation
even if they are thermodynamically favorable.
This is why our bodies have enzymes, which essentially
lower the activation energy of a reaction.
So I went ahead and drew a dotted white line
that's a little bit lower, so you
can see that when an enzyme is present,
the height of the barrier has decreased.
And if it's decreased, the reaction will proceed faster.
Now, there's one analogy that my chemistry professor used
to tell us all the time that really helped me understand
the interplay between kinetics and thermodynamics
as they apply to whether or not a reaction will occur.
So I'm going to go ahead and scroll down so we can briefly
talk about this analogy, which is
I think a fun way to think about all of this.
So let's say you went to a dating website,
because you were looking for your perfect match.
And this dating website told you that your perfect match
lived halfway across the globe.
And this is such a perfect match,
and they have all these algorithms.
And if this match were a chemical equation,
we would say that you had a very, very negative delta G
value.
That means you would be very, very spontaneous.
But you live halfway around the world,
so in terms of chemistry language,
we might say that you are kinetically limited.
That is to say, you don't have any way of actually travelling
halfway across the world to meet your special someone.
So we might say that you have a very high activation energy.
So from this discussion, perhaps the biggest take-away
is that neither kinetics nor thermodynamics solely
determines whether a reaction will proceed.
It's important to take both into account.
Now one of the applications of this,
in biochemistry especially, is remember
that enzymes lower the activation
energy of a reaction.
So we can think of enzymes as light switches.
They can regulate whether a reaction will proceed or won't
proceed.
But, of course, a light switch only
works if the light bulb itself is working.
And so the metaphor for the working light bulb
is saying that a reaction has a negative delta G value.
Or if light bulb is not working, we're
saying that the delta G value is positive.
That is, it requires a new battery or energy
for the reaction to proceed.