So I really, sincerely hope that you gave that a try because the only way you're going
to learn this is through practice.
So let's go ahead and get started.
First of all, what I have is a CH2 and a Br.
That means that's a carbon with three things coming off of it.
I'm just going to draw this and that's a carbon right there.
Okay, so I'm basically starting off with this carbon.
I actually just want to start off with the carbon and then draw the branches coming off
of it.
That's my carbon.
And what is it attached to?
Well, it's attached to two H's, a Br, but it needs four bonds, right?
So it's also attached to this stuff that's on the right of all this.
So it's attached to all the stuff that's on the right of those three things.
So that means it's also attached to that.
So what I'm going to do is I'm going to draw that I have H coming off here, H coming off
here and Br coming off here.
Does that make sense so far?
Cool.
Now what I have is that it's attached to something within parenthesis.
Do you guys remember what is this?
A CH2, right?
What happens if I have a CH2 and then units after it, a subscript after the units.
What does that mean?
Well, what it means is that I have repeating units all in a line, all in a zigzag.
What that means is that I'm going to draw this as CH2, CH2, CH2.
Does that make sense?
Because of the fact that I told you if you have a CH2 in parenthesis and it has a subscript,
that means that it's repeating.
Now notice one thing about the strategy I'm using, I'm not going straight to bondline,
instead, I'm going to like a Lewis structure and then I'm going to go ahead and turn this
into bondline.
If you try to go all in one shot, it gets more confusing that way.
So I would say first thing to do is just draw the bonds in and then you can convert it to
bondline.
So let's keep going.
Now, what is that attached to?
At the end, that's attached to a C and now let's go ahead and draw that C so that C is
right there.
Now, what are the four things that that C is attached to?
Well, it's obviously attached to the left side of the chain.
Cool.
So that means I'm missing three bonds.
So what else does it have?
Well, it has an H, so that's going to be my second bond and then it also has some weird
thing in parenthesis.
What did I say that that means if you have something other than CH2?
Let's say it's just random thing inside parenthesis that's repeating.
What does that mean?
It means they're both attached to the same carbon.
So what that means is that I have a CH2, CH3 attached as my third bond and I have my CH2,
CH3 attached as a fourth bond.
Those are my four bonds.
Let's go ahead and write them in.
I have H. Then I have CH2, CH3.
That's my third bond.
Then I have CH2, CH3.
That's my fourth bond.
Cool, right?
I know that it's a little bit tricky, but if we go step-by-step, it becomes easier.
Now that I have this drawn out, it's way easier to go to bondline.
All I do is make the zigzag pattern.
So what that means is I'm going to start off let's say with this blue carbon here.
I'm just start going across.
I have CH2, CH2, CH2, C and that C is attached to CH2, CH3 and CH2, CH3.
Remember that I don't have to draw H's, so any H that you see, don't draw it unless it's
attached to a heteroatom.
If it was attached to a heteroatom, then according to bondline rules, I wouldn't write that.
Then finally, I have a Br and a Br obviously I have to draw.
There we go.
So that is your structure right there.
Now if you maybe rotated it a little bit different, so let's say that you had drawn just anticipating
what some of you might have done, let's say you drew this going in this direction, that
is fine.
Remember that sigma bonds can freely rotate, so it doesn't matter which direction I draw
it, as long as it's all connected in the same way.