- [Instructor] What is the sum of all the solutions
to the above equation?
All right, this is interesting.
We have three plus the square root of six m,
six m minus 26 is equal to m.
So anytime you have a radical equation like this,
it's a good idea to try to isolate the radical.
So or at least you try to isolate the radical first.
So let's try to subtract three from both sides
to just be left with just the radical on the left-hand side.
And so three minus three is zero,
and on the left-hand side,
you're just left with the square root
of six m minus 26,
and that's going to be equal to m minus three.
Now to get rid of the radical,
we can square both sides of this equation.
So we'll square that side,
and then we can square that side, as well.
And so the square root of six m minus 26 squared,
that's going to be six m minus 26,
and then m minus three squared,
that's going to be m squared minus six m,
it's gonna be minus three and minus three m plus nine.
And if this step you found a little confusing,
I encourage you on Khan Academy
to review multiplying expressions,
or I'll do a quick primer right here.
M minus three times m minus three,
that's the same thing as m minus three squared.
You'll have m times m, which is m squared,
m times negative three,
which is negative three m,
negative three times m, which is negative three m,
and then negative three times negative three,
which is positive nine.
And the negative three m plus the negative three m,
that is negative six m.
And I encourage you, especially on like is on the SAT,
you would have to do this under time pressure
to be able to do things
like square a binomial like this very quickly
to realize it was gonna be m squared
plus two times the product of these.
The product of these is negative three m,
two times that is negative six m,
and then negative three times negative three
is positive nine.
So now let's see if we can solve for m.
So let's get all of, let's get all of our,
everything on the right-hand side of the equation.
So let's subtract six m from both sides.
So I'm gonna subtract six m from both sides,
and let's add 26 to both sides.
And the whole reason why I did that
is to just clean out what I have on the left-hand side.
So on the left-hand side,
I'm just gonna be left with zero.
And on the right-hand side,
I'm gonna have m squared minus 12m plus 35,
or I could write m squared minus 12m plus 35
is equal to zero.
And so let's think about the m's that satisfy this.
Well, I can factor this if I think about, well,
what two numbers have a product of 35,
but if I were to sum them, I get to negative 12?
Well 35, I can think of seven times five,
but seven plus five is positive 12.
But what about negative seven times negative five?
Well, their product is gonna be positive 35,
and negative seven plus negative five is negative 12.
So I could factor this into m minus five
times m minus seven is equal to zero.
And if this step does not make sense to you,
where I factored this quadratic,
encourage you to look up factoring quadratics
on Khan Academy to get
a little bit more practice doing that.
But if I have the product of two things
that equal zero,
that means that one or both of them
need to be equal to zero.
So m minus five could be zero,
or m minus seven would be equal to zero.
Well, to make m minus five equal to zero,
you just add five to both sides.
You would have m is equal to five,
or same thing over here, add seven to both sides.
M is equal to seven.
So the two, the two solutions are five and seven,
and if you want the sum of all the solutions,
it's going to be five plus seven is equal to 12.
And if you just wanna verify that these actually work,
try 'em out right over here.
Six times five is going to be 30 minus 26,
which is four.
The principal root of four is positive two.
Three plus two is equal to five.
It's equal to m.
And if m was seven, if m was seven,
this is gonna be three plus the square root
of 42 minus 26 is 16,
and this needs to be equal to seven.
Well, the principal root of 16 is four,
and three plus four is indeed equal to seven.