hello friends how are you, I'm the one Professor REYNER, thanks to all those
who are watching our class video keep sharing with your friends
on social networks today we we find here on our platform
to give one more exercise talking about logos soft comfort well let's do
the connections or explain the programming and then do the
double cylinder connections pneumatic effect and I hope well let's
do it with two objectives one our first objective will be to do it
direct mode and then we will indirectly explain in this very
class video I hope it helps because yes I hope you also like this
another exercise ok now moving on to matter of the exercise raises the
next situation well he made a one cylinder program
double acting with the following working conditions 11 by giving a
marcia signal or that 1 the stem number 2 comes out of the cylinder by giving a
stop signal, that is 2 the stem of the cylinder returns this implies that
we are going to start from that we have are the following items
for in the force scheme we have it assembled as follows
we have a cylinder or an actuator double acting these valves too
true they are not necessary sometimes to regulate what is the speed here
I will mention it in the program that does not will go
to infer anything in programming are throttle throttles
of unidirectional flow this solenoid valve that we are going to use here
if we need to take it into account because it is the solenoid valve is the one
we are going to send to commute in this case we are using as it is a
double acting cylinder a solenoid valve 5 winds positions like
It is a solenoid valve because it has a self in today the piloting is electric and receives
a serene and from the left side to which we will call 1 and 1 and we have a self in
today from the right side which we'll call 1 and 2 are read today from
the solenoid valves are the coils that we are going to
send a signal a pulse to her as I give you position
why is it important what is the position switching because here the
solenoid valve which by controlling the solenoid valve what we are
doing is controlling the flow of the pneumatic air pressure who is the
which gives the pneumatic energy in this case when the mount is normally on the
air pressure comes through this duct and the pressure point 1 passes the point of
connection 2 therefore is next right side of the cylinder and the chamber of the
right side to be full because the pressure so that the plunger is in
so that the plunger comes out we need the pressure to flow from
air from connection point one towards the connection point 4 when doing this then
cylinder chamber will fill to left side and the pressure will overcome from
such that the piston will remain of the cylinder all these situations the
we explain in basic pneumatics a maybe a little more space I do this
little explanation to remember to the class the same students and
all those who are new because see the need to return to
back to study large-space phase the order of the signals because we are going to
talk about sequence and that's very important you must know the positions the
signal order if you don't you're not going to be able to make or understand this situation the
raise the schedule that we we are going to press a gear that is a that
one in such a way that it will come in signal to 1 and 1 and it will make the plunger
come out the plunger is going to stay sidewalk outside because we are going to press and
we are going to stop pressing so that the plunger returns we must press a
second button which we will call a push button that 2 which is the push button
I stop doing that valve will joint position
back to its initial state the plunger will do when the pressure comes to the side
right as the plunger will return to its starting position how does this work
we press that 1 here as we see truth the pressure changes
from the connection point above was one to two because now it is
from 1 to 4 which are the two outputs to work the two exits to work are 4
and 2 then as the signs I get to left side the valve changed from
position the air came to this side left and in the bedroom the side
left and the plunger came out now we will press a second button which
is the one we will call that 2 the valve will get signal to 1 and 1 to cel
today 1 and 1 the valve changes position when
change position because of pressure of air passes from the connection point of
work output 4 to work output 2 and this is how the air will come next
right of the piston chamber of the cylinder and plunger should return to
its starting position I do it in this moment and as we can truly see the
air comes here and at a certain point we are seeing that an air
goes in and the other air goes out so right now some second
simulation air goes up through it left and air is escaping
atmosphere on the right side right now that I press again the
air stop button will enter through the right side and air is going to escape
atmosphere on the left side so that you observe the order of the arrows
and there we see the arrow that goes up and arrow going
below is working we must know because now that we come to
do this to ours the program to what we pay to run the click on the case
well the brand plc so I do not we will be able to simulate in real time
as we do in fixing but I I like I like to always support myself
the videos we make in fixing for understand the movement of the actuator
so that as we understand the order of engine spin here let's see
so we can see the actions of the cylinder we must know how he
it will work what time will it come out when to enter
that if we monitor actions and we can see how that works
ok as the example tells us that the west east of here we are going to
explain directly and so indirect we do this for
students who are beginners and let's understand this situation direct mode
is when we directly operate the selene today from iu direct mobile is when
we use a relay to then activate the coil of the
sel on today from the solenoid valve so let's do the first one which is
direct mode well here we are going to get our button
that one is an input signal so both we will only assign to one and the
program I self assign the first input because it's not busy so
both is going to be 1, entry 1 will we will put here that would be our button
ignition or in comments you let's put that 1 in simulation should
function as a push button so that it works because it will work from the
so as the program tells us that is we press on giving the signal we stop
pressing cuts the signal then it should function as push button then
here for us to understand we are going to send the output to start
read today des represent me the way out therefore the first exit is going to
to be what truth then this is going to be the
solenoid valve solenoid valve 1 and in this case the left side is the selene
today 1 and 1 then we will name it in this way
here we already have pressed the press here salt leaves the plunger of the
cylinder so now we go in we're going to now use a second button the
which we will assign as input 1 already who is who is assigned to me
represents the input signals then we will assign this and 2
this would be our stop button the which we call that 2 and we are going to here
in its parameters we will look for the parameterization we are going to put it as the
button that 2 Now we are going to how we are talking about
that we are going to actuate it directly by therefore we will assign q 2 for the
second read today from the same solenoid valve but in this case it is the
select today from the right side and who is that it represents 12 then here in
simulation we are going to this to see it as follows
when we come to each simulate we press that one is energized output 1 and 1 and the
plunger should come out because the valve position joint I stop pressing the
signal is removed but the plunger is already outside the plunger will return until
the solenoid valve changes position and for the solenoid valve to change
position you should get signal on the other extreme who is one of two
So now we come to press 1 and 2 the signal arrives at the cel in today next door
right 1 and 2 and the cylinder piston you must return to your starting position
when you must press the signal is removed but the plunger is already in if
We expand here in the parameters of simulation here the same and one is s1 as
we can see the output 11 which is 1 and 1 because it is going to light I stop pressing it
going to pay the same goes for unemployment what is that 2 and that in the programming
represents the entry and 2 we press Q2 lights up there and how can we
observe the the this has turned on from q2 when I leave
press because it will turn off and here the solenoid valve has already changed
position and therefore logically that the cylinder plunger at return ha
returned to its starting position now right here we are going to do the second one the
second exercise that is presented to us in this case here this is direct and
as we had said in our intro we will do in the same class video in
the explanation of what is direct mode and then we will also
make the explanation of what is the indirect mode then this is the mode
direct the one we just did now here previously I put it in a tab
but right now I'm putting this now we are going to use indirect mode
to make the same conditions of work that presents us here
the very indirect what it gives us is more that everything then use this relays
to be able to operate the outputs that are the exits of the one that represent me
the solenoid valve which are q1 and q2 how this works well well it should always
have my push button and one that's that one but now I'm going to operate a relay
now in in this conventional automatism
we relays call them as one with the letter k not with one q two
so on here sorry is k what q each each gene so on but
in programming already we have even explained it in the
introduction to what is plc here exist inputs there are outputs the variables
that we are going to be taking truth in this in this case because the inputs and
physical exits and well here I'm not going to talk about digital or analog for
not to confuse it but more however this let's talk about input and output and the
variables true in this case the marks or the memories
and those are going to represent the relays by the relays then here we have the
memory 1 to power what is the first
exit if I already have this um it's a memory so now i'm going to
use an auxiliary contact normally open and we will assign it
we'll name it we'll name it or we'll say that he belongs to brand 1 and
this way we are driving so hint the selene today of 1 and 1 because
pressing and 1 what we are energizing is mark 1 the same as
occurred in the relay set horrela and then when actuated this
dial 1 action to your contacts or coil of its contacts and when actuating
this contact then energize the output q1 representing the output of the brain
today on the left side 1 and 1 that same Wow
in the same way we are going to operate this in the case of sel in today when
zeal and on the right side when that we need that
the valve changes position and the cylinder plunger returns but as already
we have assigned the space of the memory 1 as this will be the brand
or memory this 2 bernal then now we use an auxiliary contact
normally open we assign it to the mark number 2
here as we can see here and now from that way we will energize the selene
today of a hole that represents in the right side solenoid valve so that
it changes position and so the plunger can return to its initial position here
in the simulation we won't see anything different more than now trigger this
the brands but what we interested is that they select the output
then we come by pressing that one that is and one is energized the brand one brand
you activate your assistant by activating your auxiliary because current passes here and
energizes the output with one that represents the selene today next door
left one and one and the same of the same way will happen in the other part
of programming when we need the cylinder piston returns to its
initial position then we come here as we can see in
the first part we press that one it energizes the brand energizes its
auxiliary contact closes normally open becomes closed
energizes the brand that does not and this is how cylinder comes out stopped pressing because they
goes out but the plunger is already out so that it returns to its initial position
we must do the same on the other side of programming so that when
we need the funnel to return to its starting position then we come here and
there as we can see that's what has happened at this bottom
we expand this bottom so that we can observe we press and one
turn on both the one mark and one that is the system the programming so that
the plunger comes out we stop pressing it turn off both we come to press and two
Mark 2 and the memory the output two shields that
represents the selene today from the side right in this case 1 and 2 so that he
return to its initial position by pressing here as we can see the
both mark 2 and q2 when stopping press because they go off well friends
this way we are finishing this video class where we were watching
how to make the connection directly and indirectly
of the actuation of a cylinder double effect but in this case a
programming to work with a logo a sim brand logo to be able to load
the program and actually doing the montage in fact I invite you to
stay in the assemblies of these is this same programming well I think that
up to here we are reaching you I appreciate that you have seen the video and if
you share it with your friends on your networks social would be great thank you very much
everyone says goodbye is the process reigns as always wishing for the best