- [Voiceover] So we've got the function
f of x is equal to two x to the third plus
five x squared minus seven.
All of that to the eighth power.
And we want to find the derivative of our
function f with respect to x.
Now the key here is to realize that this function
can be viewed as a composition of two functions.
How do we do that?
Well let me diagram it out.
So let's say we want to start with,
and I'll do it down here so we have some space.
So we're gonna start with an x and
what's the first thing that we would do?
If you were just trying to evaluate it given some x?
Well, the first thing you would take two times
that x to the third power plus five times that
x squared and then minus seven.
So, what if we imagined a function here
that just did that first part.
That just evaluated two x to the third
plus five x squared minus seven for your x.
So let's call that the function u.
So whatever you input into that function u,
you're gonna get two times that input
to the third power, plus five times that input
to the second power, minus seven.
And so when you do that, when you input with an x,
what do you output?
What do you output here?
Well, you're going to output u of x,
which is equal to two x to the third power,
plus five x squared minus seven.
And I'll do it all in one color just so
I don't have to keep changing colors.
So two x to the third power, plus
five x squared, minus seven.
That is u of x.
Now what's the next thing you're gonna do?
You're not done evaluating f of x yet.
You would then take that value and then
input into another function.
You would then take the eight power of that value.
So then, we will take that and
input it into another function.
Let's call that function v.
And that function, whatever input you give it,
and I'm using these squares just to say
whatever input goes into that function.
You're going to take it to the eighth power.
And so in this case, what do you get?
What do you end up with?
Well, you end up with v of u of x.
V of u of x.
Or you could view this as v of two x to the third,
plus five x squared, minus seven.
Or, you could view this as two x to the third,
plus five x squared, minus seven.
All of that to the eighth power.
All of that to the eighth power and that's what f of x is.
So as we just saw, f of x can be viewed
as the composition of v and u.
This is f of x.
So, if we write f of x.
If we write f of x
being equal to v of u of x,
then we see very clearly the chain rule is very useful here.
The chain rule tells us that f prime of x
is going to be the derivative of v, with respect to u.
So it's going to be v prime of, not x,
but v prime of u of x.
The derivative of v, with respect to u,
times the derivative of u, with respect to x.
So u prime of x.
So we know a few things already.
So let's, let me just write things down very clearly.
So we know that u of x is equal to two x to the third power,
plus five x squared, minus seven.
What is u prime of x?
Here we're just going to use some derivative
properties and the power rule.
Three times two is six x.
Three minus one is two, six x squared.
Two times five is 10.
Take one off that exponent, it's gonna be
10 x to the first power, or just 10 x.
And the derivative of a constant is just zero,
so we can just ignore that.
So that's u prime of x.
Now, we know that v, if we inputted an x into v,
so v of x would be equal to x to the eighth power.
V prime of x, well we just use the power rule again.
That's eight x to the seventh power.
And so v prime of u of x,
so if you were to input u of x into v prime,
well it's going to be equal to
eight times u of x to the seventh power.
Whatever you input into v prime,
you're gonna take it to the seventh power
and multiply it by eight.
So u of x and that's the same thing.
That is the same thing.
This is equal to eight times this entire expression.
U of x is two x to the third power,
plus five x squared, minus seven.
So there you have it.
F prime of x.
It is equal to this,
which we just figured out v prime of u of x is
all of this business.
So it's equal to eight, times two x to the third,
plus five x squared, minus seven.
All of that to the seventh power,
times u prime of x.
U prime of x, we figured out is that.
So times six x squared, plus ten x.
Now, as you get more practice with the chain rule,
you'll recognize this faster
and actually you won't have to right all of this down,
you'll be able to do a lot of it in your head.
You'll say, okay, I'm gonna take the derivative
of the outside function, the blue function you could say,
with respect to what I have in the inside.
So, if I was taking the derivative of x to the eighth,
it would be eight x to the seventh.
That's with respect to x.
But if I'm taking the derivative of this,
with respect to the inside, well, where I
had the x's before, I would just have this u of x.
So it's gonna be eight times this to the seventh power.
And I multiply that times the derivative of the inside.
Which is six x squared plus 10 x.