Welcome to the presentation on moments.
So just if you were wondering, I have
already covered moments.
You just may not have recognized it, because I
covered it in mechanical advantage and torque.
But I do realize that when I covered it in mechanical
advantage and torque, I think I maybe over-complicated it.
And if anything, I didn't cover some of the most basic
moment to force problems that you see in your standards
physics class, especially physics classes that aren't
focused on calculus or going to make you a mechanical
engineer the very next year.
So we did that with-- why did I write down the word
"mechanical?" Oh yeah, mechanical advantage.
If you do a search for mechanical advantage, I cover
some things on moments and also on torque.
So what is moment of force?
Well, it essentially is the same thing as torque.
It's just another word for it.
And it's essentially force times the distance to your
axis of rotation.
What do I mean by that?
Let me take a simple example.
Let's say that I have a pivot point here.
Let's say I have some type of seesaw or whatever.
There's a seesaw.
And let's say that I were to apply some force here and the
forces that we care about-- this was the exact same case
with torque, because there's essentially the same thing.
The forces we care about are the forces that are
perpendicular to the distance from our axis of rotation.
So, in this case, if we're here, the distance from our
axis of rotation is this.
That's our distance from our axis of rotation.
So we care about a perpendicular force, either a
force going up like that or a force going down like that.
Let's say I have a force going up like that.
Let's call that F, F1, d1.
So essentially, the moment of force created by this force is
equal to F1 times d1, or the perpendicular force times the
moment arm distance.
This is the moment arm distance.
That's also often called the lever arm, if you're talking
about a simple machine, and I think that's the term I used
when I did a video on torque: moment arm.
And why is this interesting?
Well, first of all, this force times distance, or this moment
of force, or this torque, if it has nothing balancing it or
no offsetting moment or torque, it's going to cause
this seesaw in this example to rotate clockwise, right?
This whole thing, since it's pivoting here, is going to
rotate clockwise.
The only way that it's not going to rotate clockwise is
if I have something keep-- so right now, this end is going
to want go down like that, and the only way that I can keep
it from happening is if I exert some upward force here.
So let's say that I exert some upward force here that
perfectly counterbalances, that keeps this whole seesaw
from rotating.
F2, and it is a distance d2 away from our axis of
rotation, but it's going in a counterclockwise direction, so
it wants to go like that.
So the Law of Moments essentially tells us, and we
learned this when we talked about the net torque, that
this force times this distance is equal to this force times
this distance.
So F1 d1 is equal to F2 d2, or if you subtract this from both
sides, you could get F2 d2 minus F1 d1 is equal to 0.
And actually, this is how we dealt with it when we talked
about torque.
Because just the convention with torque is if we have a
counterclockwise rotation, it's positive, and this is a
counterclockwise rotation in the example
that I've drawn here.
And if we have a clockwise rotation, it has a negative
torque, and that's just the convention we did, and that's
because torque is a pseudovector, but I don't want
to confuse right now.
What you'll see is that these moment problems are actually
quite, quite straightforward.
So let's do a couple.
It always becomes a lot easier when you do a problem, except
when you try to erase things with green.
So let's say that -- let me plug in real
numbers for these values.
Let me erase all of this.
Let me just erase everything.
There you go.
All right, let me draw a lever arm again.
So what we learned when we learned about torque is that
an object won't rotate if the net torque, the sum of all the
torques around it, are zero, and we're going to apply
essentially that same principle here.
So let's do it with masses, because I think that helps
explain a lot of things and makes this seesaw example a
little bit more tangible.
Let's say I have a 5-kilogram mass here, and let's say that
gravity is 10 meters per second squared.
So what is the downward force here?
What is the downward force?
It's going to be the mass times acceleration, so it's
going to be 50 Newtons.
And let's say that the distance, the moment arm
distance or the lever arm distance here, let's say that
this distance right here is 10 meters.
Let's say that I have another mass.
Let's say it's a 25 kilogram-- no, that's too much.
Let's say it's 10 kilograms. Let's say I have
a 10-kilogram mass.
And I want to place it some distance d from the fulcrum or
from the axis of rotation so that it completely balances
this 5-kilogram mass.
So how far from the axis of rotation do I put this
10-kilogram mass?
This is the distance, right?
Because we actually carry the distance to the
center of the mass.
Well, how much force is this 10-kilogram
mass exerting downwards?
Well, it's 10 kilograms times 10 meters per second squared,
it's 100 Newtons.
This is acting what?
This is acting clockwise, right?
This one's acting clockwise and this one's acting
counterclockwise, right?
So they are offsetting each other.
So we could do it a couple of ways.
We could say that 50 Newtons, the moment in the
counterclockwise direction, 50 Newtons times 10 meters, in
order for this thing to not rotate has to be equal to the
moment in the clockwise direction.
And so the moment in the clockwise direction is equal
to 100 Newtons times some distance, let's call that d,
100 Newtons times d, and then we could just
solve for d, right?
We get 50 times 10 is 500.
500 Newton-meters is equal to 100 Newtons times d.
That's 100.
Divide both sides by 100, you get 5 meters is equal to d.
So d is equal to 5.
That's interesting.
And I think this kind of confirms your intuition from
playing at the playground that you can put a heavier weight
closer to the axis of rotation to offset a light weight
that's further away.
Or the other way to put it is you could put a light weight
further away and you kind of get a mechanical advantage in
terms of offsetting the heavier weight.
So let's do a more difficult problem.
I think the more problems we do here, the more sense
everything will make.
So let's say that we have a bunch of masses.
Actually, let's not do it with masses.
Let's just do it with forces because I want to
complicate the issue.
So this is the pivot.
And let's say I have a force here that's 10 Newtons going
in the clockwise direction, and let's say it is at-- let's
say if this is 0, let's say that this is at minus 8, so
this distance is 8, right?
Let's say that I have another force going down at 5 Newtons.
And let's say that its x-coordinate is minus 6.
Let's say I have another force that's going up here, and
let's say that it is 50 Newtons.
This might get complicated.
50 Newtons, and it's at minus 2, so this distance
right here is 2.
Let's say that I need to figure out-- and I'm making
this up on the fly.
Let's say that I have another force here that is 5 Newtons.
No, let's make it a weird number, 6 Newtons, and this
distance right here is 3 meters.
And let's say that I need to figure out what force I need
to apply here upwards or downwards-- I actually don't
know, because I'm doing this on the fly-- to make sure that
this whole thing doesn't rotate.
So to make sure this whole thing doesn't rotate,
essentially what we have to say is that all of the
counterclockwise moments or all of the counter clockwise
torques have to offset all of the clockwise torques.
And notice, they're not all on the same side.
So what are all of the things that are acting in the
counterclockwise direction?
So counter clockwise is that way, right?
So this is acting counterclockwise, this is
acting counterclockwise, and that's it, right?
So the other ones are clockwise.
And we don't know this one.
Let's assume for a second.
We could assume either way.
And if we get a negative, that means it's the opposite.
So let's assume that this is a-- all of the clockwise ones
I'll do in this dark brown.
Let's assume this is clockwise, let's assume that
this is clockwise, and let's assume that our mystery force
is also clockwise.
All of the counterclockwise moments have to offset all the
clockwise moments.
So what are the counterclockwise moments?
Well, this one's counterclockwise, so it's 10
Newtons, 10 times its distance from its moment arm.
We said it's 8, because it's at the x-coordinate minus 8
from 0, so it's 10 times 8, plus 50.
This is also counterclockwise times 6, 50 times 6, and those
are all of our counterclockwise moments and
that has to equal the clockwise moments.
So clockwise moments, let's see.
We have 5 Newtons that's going clockwise times 6.
5 Newtons.
Actually, was this 6?
No, if this is 6, I must have written some other number here
that I can't read now.
How far did I say this was?
Let's say that this is 2.
So that 50, let's say this is 2, it's negative 2, because
that's what it looks like.
I apologize for confusing you.
So what were all the counterclockwise moments?
This 10 Newtons times its distance 8, the 50 Newtons
times this distance, 2.
Don't get confused by the negative.
I just kind of said we're in the x-coordinate axis or at
minus 8 if this is 0, but it's 8 units away, right?
And this 50, its moment arm distance is 2 units.
So that has to equal all of the clockwise moments.
So the clockwise moments is 5 Newtons times 6.
Its distance is 6 and it's 5 Newtons going in
the clockwise direction.
And then we have plus 6 Newtons times 3,
plus 6 times 3.
And then we're just assuming, we don't know for sure.
Let's say we're applying the force.
I should have told you ahead of time so you
could do this problem.
Let's say that we're applying the force at 10 meters away
from our fulcrum arm.
So force times 10.
So now let's just solve for the force.
We get 80 plus 100 is equal to 30 plus 18 plus 10F.
We get 180 is equal to 48 plus 10F.
What's 180 minus 48?
It's 132 is equal to 10F, or we get F is
equal to 13.2 Newtons.
So we guessed correctly that this is going to be a-- sorry,
this is going to be a-- I keep mixing up all of the clockwise
and counterclockwise.
This is going to be a clockwise force.
These were all of the-- sorry, this is going to be a
counterclockwise force, right?
A clock, this is counterclockwise.
Let me label that because I think I said it wrong several
times in the video.
So these go clockwise.
And it's this one and this one.
And what were the counterclockwise?
These go counterclockwise.
So we have to apply a 13.10 Newton force 10 meters away,
which will generate 132 Newton-meters moment in the
counterclockwise direction, which will perfectly offset
all of the other moments, and our lever will not move.
Anyway, I might have confused you with all the
counterclockwise/clockwise.
But just keep in mind that all the moments in one rotational
direction have to offset all the moments in the other
rotational direction.
All a moment is is the force times the distance from the
fulcrum arm, so force times distance from fulcrum arm.
I'll see you in the next video.