Hello young people, how are you? I'm the teacher REYNER, thank you for watching our video classes, today we will continue
making assemblies with the PLCs of the brand SIEMENS S7-200 which are that
we have on hand right now and therefore Well, we are going to continue doing the
montages and today we are going to work my actuator
double acting tire and well I hope that all the exercises
what are we doing be supportive be of help to all those who are
studying industrial automation
according to our schedule we will activate the end today from a
solenoid valve the solenoid valve we are using is a valve
pneumatic 52 therefore the first we have addressed the start button
towards iss 0.0 therefore the direction of 0.0 lo
we are going to connect the green button that is the one that we will use as
our start button now we connect the connection points in
common here so that we already have our
inputs we check when we press it should be activated there
the 0.0 which is the input that we we are using the y 0 0 now
now let's to connect to the other input that would be
the stop value and that we have directed to
and in 0.1 so we connect it here
and we will always close the loop on point
then there we already have our two outputs la y 00 and la y 0.1
now we are going to connect the outputs that we are going to be using
and in this case we will be using as output or we will determine as
drive output from solenoid valve and stable 5 guides 2
positions in this case is a pneumatic solenoid valve then
we will use the q 0.0 and 0.1 to activate the solenoid valve well then already on the
previous class we saw that the output it is also activated with the negative so
so much from the source that we will be using that I think you see there it is
the fountain What are we going to be using if you look at
let's tell something and now we are going to direct the outputs
then 0 0 towards the first path and
and here we closed the circuit on 08
in this case it multiplied from psc and here but here in the valve
the connection point we are going to take to finish pulling out the circuit in the
positive connection point of the source that we are using
now let's turn to the second the second use of mobiles
and then we will direct it to
0.1
and there we already have our and our assembly that we are going to do is
well let's do the demonstration must to have energy in this source in the
plc and cable d in this case the the program must already be loaded in
the in the cpu unit we are going to load the Program
after we load the program we are going to do a little execution
we load the program
and now we are going to make a small show for show and
then we are going to put it too we will to put is the state the program
we are going to visualize and we are going to force the inputs then now click on
the piston moves so positive outward this symbol of a
double acting actuator here we we have
sorry you weren't looking at each other a double acting actuator regulators
of unidirectional flow we have a solenoid valves five days two
positions connect also stable and well our signal input panel
is the plc then we already started now let's press our second button
what is the return to your position initial mark
that we are going to visualize that too
mass
now let's create a state of Program
the program status option so that can be visualized and go and now that
we have visualized stop running the two are read today that we have to be
activating then let's see when display the gear activation se
activates coil 1 how we see there
we see that that asset here we see that it is same to logically drop now
we come press stop it is going to activate here it will also be activated
we can activate march see you activate unemployment
an old brand and we reactivate for now we are going to force entry
let's start with the first one for example let's force up
we will force more
so we came here to our table variables
we already have in the symbol in the table state
and let's start and
to network we are going to make a statement of variables
we have to flee one
and we have coil 2
all are bit value format we start with the march add a
value of we already talked about forcing we counted the
march and as we can see we have forced a variable in this case an input the
and 0.0 that represents me to the button I go to take off I'm going to make an effort
and now to return to its position initial I will force
I will force part we change the new one value we come to current value of
right option force and return to your initial position
I must remove, I must strive as we are seeing here we will
do a second time we change the value of 0 we are going to put it in a value of 1
we return to the table where is the current value and we force and
we observe that the plunger is behind we remove the forced and we come
the row where the designated beats is to stop we change the value has 0
we give the value of 12 we come here option right
option and we give you the option to force to to return to its initial state and
then we stop trying and there we have forced entries
now to force the equal output we have to declare in
this case we have already done the declaration of the variables both in the
circle table like table of state we already have it here then
we go to the first coil for this case I should know which is the coil
what is acted in this case well that we have it outside I do not know if it is observed
off camera I did a test then we must know which is that of
noy what are we going to force in this case in basic pneumatics we saw the
position when a solenoid valve is normally meet solenoid valve
normally fine of all those states we must be very clear and right now the
plunger is out so return to your starting position
I must send a signal to the cell today from the solenoid valve next to
right then I know that in the program I have
assigned that name to that coil as the oil 2 which means winder then
I come to the ranks where the coil 2
we change value we come again to the vault where
it was current value and we click right and we force it and now
after doing this the plunger goes to return to its initial state I must
remove the forced one has to make an effort and now I'm going
to force the exit we go to the coil where is selene today from for the
exit I know that's why I tell you that one it must also be clear how they are going to do
the adapter movements I am that for the valve to come out it must receive
long left signal so that too there was a lot of exposure and in that way
then allow air to escape in this extreme and here would be the return of
air the air pressure then in this case we are going to force the coil of the
left side we expose the value of 1 right click force option and now
we hope it becomes green striving let's remove the forced to
time to force everything to play initial state and now as is out
I'm going to return it forcing us out but reinforcing then we will stop
we give the value of 1 the right option force for this return to your
starting position in this case in this example we have made the clear
demonstration of how to force of the entries and forced
output variables most variables used in what is automation
well thank you very much to all who They are watching our video class in this
case we have started work with cylinders of two the effect we expect
that this video class is helpful be of support we thank all those who
are in one way or another supporting the channel our youtube channel thank you
Have a good day everyone
and
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